Lab 10 Execution

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question 9

Post  hi hi on Thu Dec 11, 2008 1:31 pm

hi guys, i was wondering how to calculate Delta Q for question 9?

I tried sqrt((Deltam/m)^2 + (DeltadeltaT/deltaT)^2) Q total
and where m is for the water

then i tried it without the mass in the equation

i'm still confused on this question Sad

hi hi
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never mind!

Post  hi hi on Thu Dec 11, 2008 1:34 pm

that's so weird it works now o.o

i neglected the mass part of the equation above and it worked fine, my number was like 41.14 so if anyone gets a similar answer to that, you're on the right track Smile

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Question 4

Post  Jedi on Thu Dec 11, 2008 1:48 pm

I put N*m for the units of work and it's not working. Is there a problem here?

Jedi
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#4

Post  d on Thu Dec 11, 2008 1:56 pm

try using J .. how did you figure out the values

d
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#4

Post  Jedi on Thu Dec 11, 2008 2:09 pm

use Work=Force*radius*2*pi*Numberofrevolutions

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Q!

Post  meg on Thu Dec 11, 2008 4:28 pm

what is the specific heat(c) for the thermometer and the stirring rod? Anyone know?

meg
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Q1

Post  meg on Thu Dec 11, 2008 4:45 pm

NVM i found it haha

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Re: Lab 10 Execution

Post  guestttt on Fri Dec 12, 2008 1:34 pm

What is the abs Error for delta sT for question 6????????? i thought it was 0.5 but its saying im wrong

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question 6

Post  Kathleen on Fri Dec 12, 2008 2:31 pm

I don't have my manual on me but if thats the question where it asks for DeltadeltaT value (Tf-Ti) and then the absolute value of that, you use the formula

sqrt((deltaTi)^2+(deltaTf)^2) i believe...so its sqrt ((.5)^2 + (.5)^2) and i think i remember getting something like .7071 so that is probably the same value for everyone.

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question 4

Post  guest5 on Wed Dec 17, 2008 4:21 pm

Can somebody help me with question4?? pleaseee
I dont know what Im doing wrong, MApleTA marks my answer inncorect.
My data is
Force=4.5
diameter=.15m
#revolutions=1239

please help me Smile

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