Lab 10 Execution

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Lab 10 Execution

Post  dl on Mon Dec 08, 2008 7:03 pm

Does anyone know the answer to question 3 thanks.

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#3

Post  D on Mon Dec 08, 2008 7:18 pm

sqrt((Deltad/d)^2+(DeltaF/F)^2)*W

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Question7 on Maple TA

Post  A on Mon Dec 08, 2008 8:29 pm

Does anyone know how to calculate Value of DeltaQ(correct) and Value of DeltaQ(neglect mass error)?

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question 8

Post  Kathleen on Mon Dec 08, 2008 8:58 pm

Delta Q = sqrt((Deltam/m)^2+(DeltadeltaT/deltaT)^2)*Q

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Re: Lab 10 Execution

Post  Guest01 on Mon Dec 08, 2008 9:30 pm

Has anyone figured out Question 10?

Delta(W/Q) = __________________

Delta(W/Q) = sqrt((DeltaW/W)^2+(DeltaQ/Q)^2)*___

So what am I missing? Is it multiplied by something?

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Re: Lab 10 Execution

Post  Guest24 on Mon Dec 08, 2008 9:54 pm

For above you have to multiply your error by W/Q since they are asking for the absolute error. Your equation is right just multiply that by W/Q
aS asked for above I also need some help on finding Delta Q(correct) and Delta Q(neglecting mass)

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Re: Lab 10 Execution

Post  Guest01 on Mon Dec 08, 2008 10:10 pm

I tried that as well, Maple TA is marking it incorrect. At the end of my equation I add *(W/Q)

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#8

Post  D on Mon Dec 08, 2008 10:27 pm

Value of DeltaQ (correct) = sqrt((Deltam/m of water)^2+(DeltadeltaT/DeltaT)^2)*Q of water

Value of DeltaQ (neglect mass error) = sqrt((DeltadeltaT/DeltaT)^2)*Q of water

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#5 (confused)

Post  Z on Mon Dec 08, 2008 10:42 pm

sqrt((DeltaT_f)^2 + (DeltaT_i)^2)*deltaT .....what am i missing?

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Re: Lab 10 Execution

Post  question on Mon Dec 08, 2008 10:57 pm

what's the formula for question 5?

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#5

Post  D on Tue Dec 09, 2008 2:15 am

DeltadeltaT = sqrt((DeltaT_i)^2+(DeltaT_f)^2)

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question 10

Post  help1 on Tue Dec 09, 2008 1:14 pm

for question 10 i used sqrt((DeltaW/W)^2+(DeltaQ/Q)^2)*(W/Q) and it was correct

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question 8

Post  help1 on Tue Dec 09, 2008 1:21 pm

I'm stuck on the value of deltaQ(correct) and
Value of deltaQ(neglect mass error)

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units for specific heat

Post  physics on Tue Dec 09, 2008 1:30 pm

what are the units for specific heat?
i think its joules/ gram degrees c but im not sure how to enter it into maple ta for question 1
thanks

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Re: Lab 10 Execution

Post  tofu on Tue Dec 09, 2008 2:15 pm

The unit for specific heat should be cal/g/C or cal*g^-1*C^-1

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