Maple TA 26-1 Quiz

hello, i'm still not understanding this question, i tried it my way then modifying according to what was posted..

p= h/ (2 pi * m)

then square this and divide by (1.6x1-&-19) instead of by (2 * 9.1x10^-31)

that is what i tried to no avail

can someone spot what i am doing something wrong here?

soo...


KE = ((h^2)*(n^2))/(8*m*L^2)



m = mass given in problem
h = 6.6E-34
n = quantum number
L = Given Width

The number you get will be in Joules, remember to convert to MeV.


Best of Luck.

I don't think you need to square your original number.

heheh thanks, you're right!

i've tried everything and i still keep getting number 1 and 4 wrong.

What is the m in number 2?

After looking at this for a good 10 minutes I realized what these people are trying to say:

1: (h/2*pi*m) m is the number they give you, the dimension (in my post m = dimension)
((ans)^2)/(2*9.1E-31*1.6E-19) = final ans (negative)

2: same thing but divide ans^2 by 1.6E-19 instead (this didn't work, still working on a solution)

3: 2*L (given) / E-9 = ans (neg)

4: KE = ((h^2)*(n^2))/(8*m*L^2) = ans / 1.6E-13 = ans in Mev (positive)

m = mass given in problem
h = 6.6E-34
n = quantum number
L = Given Width

these are all just other people's explanations organized more clearly, if someone could post a CLEAR description of #2 please do so

Can someone please help with number 2 this is the only one I cant figure out and I have been working on this since yesterday. PLEASE HELP?????

first: h/(2*pi*the #given)=ans
then: ans/1.6E-19=final answer (neg)