Maple TA 26_2

and for #4 so take the negative of the number n...one significant digit is enough

did anyone get #2

CAN SOMEONE PLS POST WHAT THEY DID FOR QUESTION NUMBER TWO..THATS ALL I NEED AND IVE BEEN WORKING ON IT FOR A WHILE NOW.

this is what i understand from it (please correct me if I'm wrong!)

based on Slide 14: probability to observe particle at location x = (psi(x))^2

psi(x) = e^-(a*x)

ratio:

psi(x) = (e^-(a given * x given))^2 / (e^-(a given * 0))^2

e^-(a given * 0) = 1. Therefore, the ratio is just (e^-(a given * x given))^2

hope that helps

ratio:

psi(x) = (e^-(a given * x given))^2 / (e^-(a given * 0))^2

ignore the crossed out part


remember, answer is negative, as posted earlier by someone else