Ch 12.2 Help
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Re: Ch 12.2 Help
I am still having trouble with Question 3. My work:
Does 101325 really make the difference in the number?
EDIT: Found out it really doesn't.
1.1087 atm
2.595 L
24.59 C
(((1.1087*101305)*(2.595/1000))/(8.31*(273.15+24.59))*6.022e23)/1020
The answer I put: 70.9390
Does 101325 really make the difference in the number?
EDIT: Found out it really doesn't.
Guest01- Posts: 133
Join date: 2008-09-20
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It's supposed to be
((Patm*101305)*(L/1000)*6.02*10^23) then divide all of this by (celsius temp+273.15)*(8.13) to get something around 10^23 or 10^22 then divide by 10^20
((Patm*101305)*(L/1000)*6.02*10^23) then divide all of this by (celsius temp+273.15)*(8.13) to get something around 10^23 or 10^22 then divide by 10^20
student- Guest
Re: Ch 12.2 Help
Doing that I get a value of 112.xxxx
I don't know if one of the constants I'm using is wrong or what.
I guess I can sacrifice 1 point.
I don't know if one of the constants I'm using is wrong or what.
I guess I can sacrifice 1 point.
Guest01- Posts: 133
Join date: 2008-09-20
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