Ch 12.2 Help

Post new topic   Reply to topic

Page 2 of 2 Previous  1, 2

View previous topic View next topic Go down

Re: Ch 12.2 Help

Post  Avagadro on Fri Nov 21, 2008 1:35 am

no typo.. I'm a distant relative of Avogadro

Avagadro
Guest


Back to top Go down

Re: Ch 12.2 Help

Post  Guest01 on Fri Nov 21, 2008 2:47 am

I am still having trouble with Question 3. My work:
1.1087 atm
2.595 L
24.59 C

(((1.1087*101305)*(2.595/1000))/(8.31*(273.15+24.59))*6.022e23)/1020

The answer I put: 70.9390


Does 101325 really make the difference in the number?

EDIT: Found out it really doesn't.

Guest01

Posts: 133
Join date: 2008-09-20

View user profile

Back to top Go down

most recent question

Post  student on Fri Nov 21, 2008 3:28 am

It's supposed to be
((Patm*101305)*(L/1000)*6.02*10^23) then divide all of this by (celsius temp+273.15)*(8.13) to get something around 10^23 or 10^22 then divide by 10^20

student
Guest


Back to top Go down

Re: Ch 12.2 Help

Post  Guest01 on Fri Nov 21, 2008 4:34 am

Doing that I get a value of 112.xxxx

I don't know if one of the constants I'm using is wrong or what.

I guess I can sacrifice 1 point.

Guest01

Posts: 133
Join date: 2008-09-20

View user profile

Back to top Go down

signs

Post  jsyz on Fri Nov 21, 2008 11:47 am

1.)-
2.)-
3.)+
4.)-

jsyz
Guest


Back to top Go down

Page 2 of 2 Previous  1, 2

View previous topic View next topic Back to top


Permissions of this forum:
You can reply to topics in this forum