Ch 14.2 Help

when is 14.2 due? monday? or was it due already on friday?

thanksss

It is due on this coming Wednesday actually

Just a note, The answer for Question 2 is POSITIVE, because on Maple TA it doesnt ask to indicate with a negative/positive sign or anything. Just letting you know..

My question 2 is different from the one posted, this is how it reads....

An ideal gas changes its pressure and volume as shown in the PV-diagram starting at point A and returning to it. The pressure PAB is 2.786 atm and volume VB is 233.5 cm3. The pressure at C is 1 atmosphere. How many calories are exchanged with the environment? (Hint: What is the relationship between the work done and the area of the triangle shown?) Indicate with a positive (negative) sign whether heat is put into (taken out of) the gas.

how do you solve for this question?

I have the same question 2 that you do and I do not know how to figure it out does anyone have any ideas?

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That's weird that you guys have a different question 2.

I think what you have to do is the same concept as posted above, because since W=p*change in V, even though they now give you a pressure for C, which changes from C to A, the volume still does not change (so I believe, I'm not sure if your picture looks different also). This means that the W will still equal 0. Try using the above formula and ignoring the additional information about C. If this doesnt work then I'll try thinking of something else.

An ideal gas changes its pressure and volume as shown in the PV-diagram starting at point A and returning to it. The pressure PAB is 2.786 atm and volume VB is 233.5 cm3. The pressure at C is 1 atmosphere. How many calories are exchanged with the environment? (Hint: What is the relationship between the work done and the area of the triangle shown?) Indicate with a positive (negative) sign whether heat is put into (taken out of) the gas.

I think you would still do 2.786*101300 = __
233.5 / 1000000 = 1e-4(volume at point A)-2.335e-4 = -1.335e-4
W(AB)= (2.786*101300)*(-1.335e-4) = -#
And then find the Work from B->C
Volume change would be (2.335e-4-1e-4) = 1.335e-4
And then I don't know if you would do a pressure change (as in PB-PC) or just do the 1atm*101300
but it would be Work(BC) = Pressure * 1.335e-4 = ___
and then add those two answers together and divide by 4.187 to put into calories

I don't have a calculator on me so I can't work out the problem right now but I think that should work

I tried that method for question 2 its not working.

Yeah, question 2 on maple TA reads different for me as well

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Well can someone with the alternative question 2 post their question again with the answer given so that we can work on it?

the question that i posted is from maple ta not the cd so I dont have what the answer should be....

sorry...

I'm sorry, I got the questions and answers from the website that engelmann posted up on blackboard in the beginning of the semester to allow us to do 'practice' questions. So far, the questions have been the same so I didn't realize that #2 was a different on this quiz this time. Although, I still don't know how to do question 2, I'll repost the correct question.

An ideal gas changes its pressure and volume as shown in the PV-diagram starting at point A and returning to it. The pressure PAB is 2.503 atm and volume VB is 299.1 cm3. The pressure at C is 1 atmosphere. How many calories are exchanged with the environment? (Hint: What is the relationship between the work done and the area of the triangle shown?) Indicate with a positive (negative) sign whether heat is put into (taken out of) the gas.

If someone knows how to do this question please post an answer because many of us have this question and don't know how to do it. Thanks.