Ch 9.3 Help
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Re: Ch 9.3 Help
Question 2
KE= 1/2kx^2-mgx
straight off the lecture notes. the method posted above does not work
KE= 1/2kx^2-mgx
straight off the lecture notes. the method posted above does not work
1- Guest
Re: Ch 9.3 Help
The first formula for Question 2 worked for me. Just remember if you find the square root then in the KE formula you have to square the v again. You can also just leave it as is and do .5*m*v (not squared).
Guest01- Posts: 133
Join date: 2008-09-20
Question 1
Alright, first list all the given quantities
PE = some# (check!)
k = some# (check!)
Now what is the question, what are you looking for? How far has the spring compressed? (In other words, the distance x )
x = ? <------- unknown, which also happens to be the answer
Think of an appropritate equation/formula that would satisfy the problem.
Well, PE = 1/2*k*x^2 pops into mind, don't you agree?
Okay, so now solve for the unknown, the x
So: PE = 1/2*k*x^2
Then: PE / (.5*k) = x^2
Therefore: sqrt [ PE / (.5*k) ] = x
PE = some# (check!)
k = some# (check!)
Now what is the question, what are you looking for? How far has the spring compressed? (In other words, the distance x )
x = ? <------- unknown, which also happens to be the answer
Think of an appropritate equation/formula that would satisfy the problem.
Well, PE = 1/2*k*x^2 pops into mind, don't you agree?
Okay, so now solve for the unknown, the x
So: PE = 1/2*k*x^2
Then: PE / (.5*k) = x^2
Therefore: sqrt [ PE / (.5*k) ] = x
Shrubbs- Posts: 3
Join date: 2008-10-31
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