Ch 9.3 Help

Post new topic   Reply to topic

Page 2 of 2 Previous  1, 2

View previous topic View next topic Go down

Re: Ch 9.3 Help

Post  1 on Thu Oct 30, 2008 4:01 pm

Question 2
KE= 1/2kx^2-mgx

straight off the lecture notes. the method posted above does not work

1
Guest


Back to top Go down

email address for prof dawber

Post  an on Thu Oct 30, 2008 11:28 pm

"Matthew Dawber" <matthew.dawber@stonybrook.edu>

hope that helps

an
Guest


Back to top Go down

Re: Ch 9.3 Help

Post  Guest01 on Fri Oct 31, 2008 1:37 am

The first formula for Question 2 worked for me. Just remember if you find the square root then in the KE formula you have to square the v again. You can also just leave it as is and do .5*m*v (not squared).

Guest01

Posts: 133
Join date: 2008-09-20

View user profile

Back to top Go down

Question 1

Post  Shrubbs on Fri Oct 31, 2008 1:13 pm

Alright, first list all the given quantities

PE = some# (check!)
k = some# (check!)

Now what is the question, what are you looking for? How far has the spring compressed? (In other words, the distance x )

x = ? <------- unknown, which also happens to be the answer


Think of an appropritate equation/formula that would satisfy the problem.

Well, PE = 1/2*k*x^2 pops into mind, don't you agree?

Okay, so now solve for the unknown, the x

So: PE = 1/2*k*x^2
Then: PE / (.5*k) = x^2
Therefore: sqrt [ PE / (.5*k) ] = x

Shrubbs

Posts: 3
Join date: 2008-10-31

View user profile

Back to top Go down

Page 2 of 2 Previous  1, 2

View previous topic View next topic Back to top


Permissions of this forum:
You can reply to topics in this forum