ch. 9_1 quiz

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Question regarding question 3

Post  BGGirl on Sun Oct 26, 2008 9:43 pm

For question number 4 why do we disregard the time associated with the velocity? scratch


Thanks

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Re: ch. 9_1 quiz

Post  aa on Sun Oct 26, 2008 10:09 pm

plz help with 3

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why does #4 not work?

Post  wtf on Sun Oct 26, 2008 10:53 pm

#4 keeps coming out wrong for me i've done it like 6 times and i've done it exactly how everyone has said to do it so does anyone else have any ideas? scratch

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Q4

Post  cyn on Sun Oct 26, 2008 11:36 pm

Ok they ask for
V= ? ( magnitud of velocity)
so:
V= -(V_o)(sin(2pi*f*t))
ex:
given:
f= 2.499 HZ
V(V_o)= -3.747m/s (V_o is always linear m/s)
t=.1062 s
so
V= -(-3.747m/s)(sin(2pi*2.499*.1062))
V=3.729
Ps. remember there is more than one way to use w, 3:
w=2(pi)*f
w= 2(pi)/ T
w= theta/t
Hope this helps you

cyn
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questions 3 & 4

Post  guest1 on Sun Oct 26, 2008 11:52 pm

you have to put ur calculator in radian mode for both questions

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Q4

Post  cyn on Sun Oct 26, 2008 11:52 pm

V_o= max veloc.
V= magnitud of maximum velocity.

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Re: ch. 9_1 quiz

Post  an on Mon Oct 27, 2008 12:31 am

switch your calc mode to radians for #3 and 4 and use the equations in the post with the red

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Re: ch. 9_1 quiz

Post  Guest01 on Mon Oct 27, 2008 1:27 am

Have you checked above?

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