Maple TA Quiz 172
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Re: Maple TA Quiz 172
Question 4: I1 + I2. The answer is negative.
Answer may differ if a different image is loaded in your quiz (for this particular question).
Answer may differ if a different image is loaded in your quiz (for this particular question).
helping Guest
#2
thanks, but could u explain how u got the answer for #2? i tried using the R = p(L/A) and P = (V/R)V formulas, but i couldnt figure it out. thanks
at Guest
Re: Maple TA Quiz 172
Regarding the question above:
Here's how I did it: First I wrote out the equation R=p(L/A) so that it looked like this: R=p(L/(pi*r^2)). I wrote out the equations, one of them having the value provided (mine was 1.2 something) multiplied onto the r: R=p(L/(pi*r^2)) & R(prime)=p(L/(pi*(1.2r)^2)).
At this point, you can begin calculating the proportion: R/R(prime) = (p(L/(pi*r^2)))/(p(L/(pi*(1.2r)^2)))
Once all is said and done (and you've eliminated all like terms  p, L, pi, r^2), you're left with that same value provided, only squared. And that's your answer.
I hope that helps.
Here's how I did it: First I wrote out the equation R=p(L/A) so that it looked like this: R=p(L/(pi*r^2)). I wrote out the equations, one of them having the value provided (mine was 1.2 something) multiplied onto the r: R=p(L/(pi*r^2)) & R(prime)=p(L/(pi*(1.2r)^2)).
At this point, you can begin calculating the proportion: R/R(prime) = (p(L/(pi*r^2)))/(p(L/(pi*(1.2r)^2)))
Once all is said and done (and you've eliminated all like terms  p, L, pi, r^2), you're left with that same value provided, only squared. And that's your answer.
I hope that helps.
helping Guest
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