Maple Quiz 18.3
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Maple Quiz 18.3
did anyone get #1 and 4? i used the equation in the lecture notes but im not getting it right.
maple sy Guest
Re: Maple Quiz 18.3
#1 is simply I(current) * A(area)
make sure you convert the length to meters. & just square it to find the area. the answer is POSITIVE.
I can't get #4 either...anyone know?
make sure you convert the length to meters. & just square it to find the area. the answer is POSITIVE.
I can't get #4 either...anyone know?
entee Guest
Re: Maple Quiz 18.3
actually i figured out #4...it's because you have to convert your final answer to electron volts
1 eV = 1.602 J
answer is NEGATIVE
1 eV = 1.602 J
answer is NEGATIVE
entee Guest
Re: Maple Quiz 18.3
1) Area *current
2) PE=((area*0.0001)*I)*(magnetic field)*cos0 … answer is negative.
3) u=(qvr)/2 … q=1.6*10^19 … answer is negative.
4) This one is really weird… but… multiply the two given number together. Multiply that by two. Then divide it by 1.602. and then finally, multiply it by 10^19.
2) PE=((area*0.0001)*I)*(magnetic field)*cos0 … answer is negative.
3) u=(qvr)/2 … q=1.6*10^19 … answer is negative.
4) This one is really weird… but… multiply the two given number together. Multiply that by two. Then divide it by 1.602. and then finally, multiply it by 10^19.
juggy Posts : 1
Join date : 20090219
how
thanks very much for all the help guys.. this site has been very helpful!
but physics has been very difficult subject for me.. how do you study this course? are there any advice that you would like to share?
but physics has been very difficult subject for me.. how do you study this course? are there any advice that you would like to share?
thanks Guest
Re: Maple Quiz 18.3
#4 still wont work for me...i tried doing it following the example on sheet 38 and then when i got the answer in joules i divided it by 1.602 to put into eV but it still didnt work..any other suggestions?
me Guest
#2
I have tried number 2 so many times but its not working for me can someone please post a detailed description of how to do this problem?
sck105 Guest
question 2
thank you guys soo much for your help!
so far i am still stuck on number 2 however.
I thought it was just ((Area x 1E4) * (Current I) * (Magnetic Field B) * cos(90)
and the answer would be negative
but this answer is not accepted o.o
is there something else i am leaving out or missing?
thank you so much for your time and help!
so far i am still stuck on number 2 however.
I thought it was just ((Area x 1E4) * (Current I) * (Magnetic Field B) * cos(90)
and the answer would be negative
but this answer is not accepted o.o
is there something else i am leaving out or missing?
thank you so much for your time and help!
:) Guest
question 2
okay icic. instead of the cos 90, i had to use the angle given, duh! lol
thank youu!!
thank youu!!
:) Guest
#2
No matter what I do I still cannot get #2.
Here are my numbers: area=31.15cm^2, current=.1609A, angle relative to direction of uniiform magnetic field=166.84, magnetic field=0.15T
When I put it in to the equation:
PE= ((31.15*.0001)*.1609)*(0.15)*cos(166.84)
I've tried this so many times and it keeps telling me I'm wrong!
Can anyone help?
Here are my numbers: area=31.15cm^2, current=.1609A, angle relative to direction of uniiform magnetic field=166.84, magnetic field=0.15T
When I put it in to the equation:
PE= ((31.15*.0001)*.1609)*(0.15)*cos(166.84)
I've tried this so many times and it keeps telling me I'm wrong!
Can anyone help?
lost Guest
lost #2
I redid your problem and got an answer of 0.000073. I did notice that you did not use a "" sign in front of the formula that you posted. I also put in ...*(cos(16.84)) when I did the calculaiton. This might have gummed up the answer as well. Let me know how you made out.
super mo Guest
Q #2
A wire loop with a 26.91 cm2 area carrying a 0.2981 A current has its magnetic moment directed at an angle of 151.380 relative to the direction of a uniform magnetic field of 0.15 T in which the loop is placed. What is the potential energy of the magnetic dipole (see sheet 3238) ? Indicate with a positive (negative) sign whether the minimum potential energy is at 900 (00).
(( A* .0001)*I)*(Magnetic field)*(cos151.380)
I have tried many times this question and when I do my calculation i get the asnwer of 1.056E8. I don't know why its not working.
Any help?
(( A* .0001)*I)*(Magnetic field)*(cos151.380)
I have tried many times this question and when I do my calculation i get the asnwer of 1.056E8. I don't know why its not working.
Any help?
phent Guest
#4
Look at pg 38. On the bottom it states: delta U= 2uB Just plug in what they gave you and divide by1.6*1019. You need to divide by this number in order for your answer to be in electron volts. ALWAYS scan through previoius posts before asking for help. You can usually find the answer you are lookng for.
super mo Guest
Phet
I plugged in your #'s and did not get that answer look at what I posted agove and see if that helps EX: Your formla did not contain a "" sign
super mo Guest
#2
your calculator has to be in degrees for number 2..... i felt really silly when i got found that out
JJ Guest
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