Maple TA 19_2
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Maple TA 19_2
#1 omega=(2pi)/time in seconds given
epsilon_max= omega*B*A
as usual don't forget to convert cm to m where A=L^2
epsilon_max= omega*B*A
as usual don't forget to convert cm to m where A=L^2
super mo Guest
#3
secondary coil turns / factor of increased input voltage
answer positive
no clue on number 2
answer positive
no clue on number 2
super mo Guest
#4
I_1V_1=I_2V_2 solve for I_1
V_1= 1159.4
V_2= 155.6
I_2= 6.237
I_1= ?
answer + 0.837051
stil no clue on #2
V_1= 1159.4
V_2= 155.6
I_2= 6.237
I_1= ?
answer + 0.837051
stil no clue on #2
super mo Guest
Question #2
(%/100)/2pi = your answer (which is negative)
Note** pi = 3.14
For example: Percentage given = 30.86
.3086/(2*3.14)=0.049115 (answer is negative)
Note** pi = 3.14
For example: Percentage given = 30.86
.3086/(2*3.14)=0.049115 (answer is negative)
Mer... I Guest
Q3
Hey, im glad i can actually help because usually when i come here the answers are already posted.
q3 is simply:
#turns/factor ( second number in the question/first)
answer is positive
glad i can help and thanks to everyone who constantly helps the rest of us out
q3 is simply:
#turns/factor ( second number in the question/first)
answer is positive
glad i can help and thanks to everyone who constantly helps the rest of us out
manny Guest
Q2
My number 2 isnt working
I did :
58.16/100/(2pi)=.0926
didn't work. help please. thanks.
I did :
58.16/100/(2pi)=.0926
didn't work. help please. thanks.
Guest22 Guest
Re: Maple TA 19_2
for 192 #2
its sin inverse of % say .8990 and then divide that # by 2*pi and the answer is negative
make sure ur calculators r in radian, weird but works
its sin inverse of % say .8990 and then divide that # by 2*pi and the answer is negative
make sure ur calculators r in radian, weird but works
gr8luck Posts : 5
Join date : 20080918
question 2
I don't understand question 2. I have 57.65 as my percentage.
I am doing .5765/2*pi, and getting 0.092. Its incorrect. what am i doing wrong???
thanks!!!
I am doing .5765/2*pi, and getting 0.092. Its incorrect. what am i doing wrong???
thanks!!!
helpme2 Guest
19_2
This worked for me:
inverse sin( 87.37/100)= 1.06275703
take that answer / (2pi) = .1691430346.
inverse sin( 87.37/100)= 1.06275703
take that answer / (2pi) = .1691430346.
hey ever Guest
Q 2
Hey...i tried that answer, but it didn't work. where are you getting the number that you are taking the inverse sin of?
helpme2 Guest
#2
Hey great work mer...1 and gr8luck. I have no idea how you got this one. my%was 63.1 so..
sin^1(0.631) then divide that by 2*pi. That should work. good luck on the exam all!!
OH GREAT GOD OF PHYSICS HERE MY PRAYER. AND HAIL TO THE ANGELS OF PARTIAL CREDIT.
sin^1(0.631) then divide that by 2*pi. That should work. good luck on the exam all!!
OH GREAT GOD OF PHYSICS HERE MY PRAYER. AND HAIL TO THE ANGELS OF PARTIAL CREDIT.
super mo Guest
radian mode?
how would we know if we had to switch to radian mode if they didnt tell us...? like on the test for example...
guest123 Guest
radian mode
Thye told us to switch to Radian mode for question #2 and I am sure that they will tell us on the exams as well. When I approached the professor about when to use degrees/ radians he did tell me that radians are the SI unit so if nothing is given in degrees use radian mode to get the answer in radians and you should be okay. Hope this helps. Good luck on the exam on Monday everyone!
anon Guest
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