Maple TA 19_2

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Maple TA 19_2

Post  super mo on Sun Feb 22, 2009 3:09 pm

#1 omega=(2pi)/time in seconds given
epsilon_max= omega*B*A
as usual don't forget to convert cm to m where A=L^2

super mo
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#3

Post  super mo on Sun Feb 22, 2009 3:45 pm

secondary coil turns / factor of increased input voltage
answer positive
-no clue on number 2

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#4

Post  super mo on Sun Feb 22, 2009 3:56 pm

I_1V_1=I_2V_2 solve for I_1
V_1= 1159.4
V_2= 155.6
I_2= 6.237
I_1= ?
answer + 0.837051
stil no clue on #2

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Q#2

Post  PHY122 on Tue Feb 24, 2009 6:45 pm

Any ideas on Q#2 yet?

PHY122
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Question #2

Post  Mer... I on Wed Feb 25, 2009 2:53 am

(%/100)/2pi = your answer (which is negative)
Note** pi = 3.14

For example: Percentage given = 30.86

.3086/(2*3.14)=0.049115 (answer is negative)

Sleep

Mer... I
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Q3

Post  manny on Wed Feb 25, 2009 4:00 am

Hey, im glad i can actually help because usually when i come here the answers are already posted.


q3 is simply:

#turns/factor ( second number in the question/first)

answer is positive

glad i can help and thanks to everyone who constantly helps the rest of us out Smile

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Q2

Post  Guest22 on Wed Feb 25, 2009 1:16 pm

My number 2 isnt working

I did :
58.16/100/(2pi)=-.0926

didn't work. help please. thanks.

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Re: Maple TA 19_2

Post  gr8luck on Wed Feb 25, 2009 4:21 pm

for 19-2 #2

its sin inverse of % say .8990 and then divide that # by 2*pi and the answer is negative

make sure ur calculators r in radian, weird but works

gr8luck

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question 2

Post  helpme2 on Wed Feb 25, 2009 11:40 pm

I don't understand question 2. I have 57.65 as my percentage.

I am doing .5765/2*pi, and getting 0.092. Its incorrect. what am i doing wrong???

thanks!!!

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19_2

Post  hey ever on Thu Feb 26, 2009 10:51 am

This worked for me:


inverse sin( 87.37/100)= 1.06275703
take that answer / (2pi) = .1691430346.

Smile

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Q 2

Post  helpme2 on Thu Feb 26, 2009 11:43 am

Hey...i tried that answer, but it didn't work. where are you getting the number that you are taking the inverse sin of?

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#2

Post  super mo on Thu Feb 26, 2009 3:56 pm

Hey great work mer...1 and gr8luck. I have no idea how you got this one. my%was 63.1 so..
sin^-1(0.631) then divide that by 2*pi. That should work. good luck on the exam all!!
OH GREAT GOD OF PHYSICS HERE MY PRAYER. AND HAIL TO THE ANGELS OF PARTIAL CREDIT.

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#2

Post  anonymou on Thu Feb 26, 2009 10:07 pm

make sure u r in radian mode for doing no. 2.

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radian mode?

Post  guest123 on Fri Feb 27, 2009 1:31 am

how would we know if we had to switch to radian mode if they didnt tell us...? like on the test for example...

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Q4

Post  helpz0r on Fri Feb 27, 2009 12:07 pm

simple algebra:
I_1 =(I_2*V_2)/V_1 answer (+)

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radian mode

Post  anon on Sat Feb 28, 2009 8:40 pm

Thye told us to switch to Radian mode for question #2 and I am sure that they will tell us on the exams as well. When I approached the professor about when to use degrees/ radians he did tell me that radians are the SI unit so if nothing is given in degrees use radian mode to get the answer in radians and you should be okay. Hope this helps. Good luck on the exam on Monday everyone!

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Re: Maple TA 19_2

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