# Maple TA 26-1 Quiz

## Maple TA 26-1 Quiz

Does anyone know how to do questions 2 and 3?

sck105
Guest

## Questions

does anyone know how to do any of them at all????

Guest 91
Guest

## Hint on this section of Hw

You MUST go past the sheets that is stated in the question for 26_1, 2, and 3. Go through all of the lecture sheets.
To get you started on 26_1 #1
Delta P= h/(2pim) where m is given
plug answer into KE = (P)^2/92*9.1*10^-31 then convert to eV

super mo
Guest

## question 2 and 3

can someone plz help with number 2 and 3?

sck105
Guest

## question 3 and 4

Does anyone have any idea how to do questions 3 and 4 on this I am really struggling.....please help me????

hwilson
Guest

## question 2 and 3

I am really having trouble with 2 and 3 as well anyone have anything?

craziecu
Guest

## number 2

You are using the same equation as for number 1, but no need to divide by (2 * 9.1e-31) just divide by 1.6e-19.

phy-six
Guest

## question 3

Basically 2* L (given), convert to nm. Answer is negative.

phy-six
Guest

phy-six
Guest

sjames
Guest

## question 1 and 4

I have tried everything for number one and four can someone please post a detailed description of how they solved it????????????? pleassseee?

cuteprin
Guest

## question 4

please someone kindly help out! I've been stuck on question 4 for a long while! thanks!

Guest123
Guest

## Number 4 Hint

For number 4 the numbers you are getting are in J, you'd like them in MeV...the conversion is 1.609E-13J = 1 MeV. Best of luck.

6 more c
Guest

## Re: Maple TA 26-1 Quiz

Oh yea, and use the formula on Sheet 16'.

6 more c
Guest

## question 4

Can you explain how to do it (the question not the conversion) cuz I cant figure it out?

sck105
Guest

## number 2

hello, i'm still not understanding this question, i tried it my way then modifying according to what was posted..

p= h/ (2 pi * m)

then square this and divide by (1.6x1-&-19) instead of by (2 * 9.1x10^-31)

that is what i tried to no avail

can someone spot what i am doing something wrong here?

:)
Guest

## Re: Maple TA 26-1 Quiz

soo...

KE = ((h^2)*(n^2))/(8*m*L^2)

m = mass given in problem
h = 6.6E-34
n = quantum number
L = Given Width

The number you get will be in Joules, remember to convert to MeV.

Best of Luck.

6 more c
Guest

I don't think you need to square your original number.

6 more c
Guest

## thank you 6 more c

heheh thanks, you're right!

:)
Guest

## Help!

i've tried everything and i still keep getting number 1 and 4 wrong.

Delilah
Guest

## Re: Maple TA 26-1 Quiz

What is the m in number 2?

Sss
Guest

## Hey

After looking at this for a good 10 minutes I realized what these people are trying to say:

1: (h/2*pi*m) m is the number they give you, the dimension (in my post m = dimension)
((ans)^2)/(2*9.1E-31*1.6E-19) = final ans (negative)

2: same thing but divide ans^2 by 1.6E-19 instead (this didn't work, still working on a solution)

3: 2*L (given) / E-9 = ans (neg)

4: KE = ((h^2)*(n^2))/(8*m*L^2) = ans / 1.6E-13 = ans in Mev (positive)

m = mass given in problem
h = 6.6E-34
n = quantum number
L = Given Width

these are all just other people's explanations organized more clearly, if someone could post a CLEAR description of #2 please do so

Leland
Guest

sjames
Guest

## Q #2

first: h/(2*pi*the #given)=ans

Guest001
Guest