Maple TA 261 Quiz
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Hint on this section of Hw
You MUST go past the sheets that is stated in the question for 26_1, 2, and 3. Go through all of the lecture sheets.
To get you started on 26_1 #1
Delta P= h/(2pim) where m is given
plug answer into KE = (P)^2/92*9.1*10^31 then convert to eV
To get you started on 26_1 #1
Delta P= h/(2pim) where m is given
plug answer into KE = (P)^2/92*9.1*10^31 then convert to eV
super mo Guest
question 3 and 4
Does anyone have any idea how to do questions 3 and 4 on this I am really struggling.....please help me????
hwilson Guest
number 2
You are using the same equation as for number 1, but no need to divide by (2 * 9.1e31) just divide by 1.6e19.
physix Guest
question 4
Follow the problem on page 22 of the CD, your final answer will be in eV, just convert to megaeV and you get your final answer. Answer is positive.
physix Guest
question 1 and 4
I have tried everything for number one and four can someone please post a detailed description of how they solved it????????????? pleassseee?
cuteprin Guest
question 4
please someone kindly help out! I've been stuck on question 4 for a long while! thanks!
Guest123 Guest
Number 4 Hint
For number 4 the numbers you are getting are in J, you'd like them in MeV...the conversion is 1.609E13J = 1 MeV. Best of luck.
6 more c Guest
question 4
Can you explain how to do it (the question not the conversion) cuz I cant figure it out?
sck105 Guest
number 2
hello, i'm still not understanding this question, i tried it my way then modifying according to what was posted..
p= h/ (2 pi * m)
then square this and divide by (1.6x1&19) instead of by (2 * 9.1x10^31)
that is what i tried to no avail
can someone spot what i am doing something wrong here?
p= h/ (2 pi * m)
then square this and divide by (1.6x1&19) instead of by (2 * 9.1x10^31)
that is what i tried to no avail
can someone spot what i am doing something wrong here?
:) Guest
Re: Maple TA 261 Quiz
soo...
KE = ((h^2)*(n^2))/(8*m*L^2)
m = mass given in problem
h = 6.6E34
n = quantum number
L = Given Width
The number you get will be in Joules, remember to convert to MeV.
Best of Luck.
KE = ((h^2)*(n^2))/(8*m*L^2)
m = mass given in problem
h = 6.6E34
n = quantum number
L = Given Width
The number you get will be in Joules, remember to convert to MeV.
Best of Luck.
6 more c Guest
Hey
After looking at this for a good 10 minutes I realized what these people are trying to say:
1: (h/2*pi*m) m is the number they give you, the dimension (in my post m = dimension)
((ans)^2)/(2*9.1E31*1.6E19) = final ans (negative)
2: same thing but divide ans^2 by 1.6E19 instead (this didn't work, still working on a solution)
3: 2*L (given) / E9 = ans (neg)
4: KE = ((h^2)*(n^2))/(8*m*L^2) = ans / 1.6E13 = ans in Mev (positive)
m = mass given in problem
h = 6.6E34
n = quantum number
L = Given Width
these are all just other people's explanations organized more clearly, if someone could post a CLEAR description of #2 please do so
1: (h/2*pi*m) m is the number they give you, the dimension (in my post m = dimension)
((ans)^2)/(2*9.1E31*1.6E19) = final ans (negative)
2: same thing but divide ans^2 by 1.6E19 instead (this didn't work, still working on a solution)
3: 2*L (given) / E9 = ans (neg)
4: KE = ((h^2)*(n^2))/(8*m*L^2) = ans / 1.6E13 = ans in Mev (positive)
m = mass given in problem
h = 6.6E34
n = quantum number
L = Given Width
these are all just other people's explanations organized more clearly, if someone could post a CLEAR description of #2 please do so
Leland Guest
question 2
Can someone please help with number 2 this is the only one I cant figure out and I have been working on this since yesterday. PLEASE HELP?????
sjames Guest
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