# Maple TA 26-1 Quiz

## Hint on this section of Hw

You MUST go past the sheets that is stated in the question for 26_1, 2, and 3. Go through all of the lecture sheets.

To get you started on 26_1 #1

Delta P= h/(2pim) where m is given

plug answer into KE = (P)^2/92*9.1*10^-31 then convert to eV

To get you started on 26_1 #1

Delta P= h/(2pim) where m is given

plug answer into KE = (P)^2/92*9.1*10^-31 then convert to eV

**super mo**- Guest

## question 3 and 4

Does anyone have any idea how to do questions 3 and 4 on this I am really struggling.....please help me????

**hwilson**- Guest

## number 2

You are using the same equation as for number 1, but no need to divide by (2 * 9.1e-31) just divide by 1.6e-19.

**phy-six**- Guest

## question 4

Follow the problem on page 22 of the CD, your final answer will be in eV, just convert to megaeV and you get your final answer. Answer is positive.

**phy-six**- Guest

## question 1 and 4

I have tried everything for number one and four can someone please post a detailed description of how they solved it????????????? pleassseee?

**cuteprin**- Guest

## question 4

please someone kindly help out! I've been stuck on question 4 for a long while! thanks!

**Guest123**- Guest

## Number 4 Hint

For number 4 the numbers you are getting are in J, you'd like them in MeV...the conversion is 1.609E-13J = 1 MeV. Best of luck.

**6 more c**- Guest

## question 4

Can you explain how to do it (the question not the conversion) cuz I cant figure it out?

**sck105**- Guest

## number 2

hello, i'm still not understanding this question, i tried it my way then modifying according to what was posted..

p= h/ (2 pi * m)

then square this and divide by (1.6x1-&-19) instead of by (2 * 9.1x10^-31)

that is what i tried to no avail

can someone spot what i am doing something wrong here?

p= h/ (2 pi * m)

then square this and divide by (1.6x1-&-19) instead of by (2 * 9.1x10^-31)

that is what i tried to no avail

can someone spot what i am doing something wrong here?

**:)**- Guest

## Re: Maple TA 26-1 Quiz

soo...

KE = ((h^2)*(n^2))/(8*m*L^2)

m = mass given in problem

h = 6.6E-34

n = quantum number

L = Given Width

The number you get will be in Joules, remember to convert to MeV.

Best of Luck.

KE = ((h^2)*(n^2))/(8*m*L^2)

m = mass given in problem

h = 6.6E-34

n = quantum number

L = Given Width

The number you get will be in Joules, remember to convert to MeV.

Best of Luck.

**6 more c**- Guest

## Hey

After looking at this for a good 10 minutes I realized what these people are trying to say:

1: (h/2*pi*m) m is the number they give you, the dimension (in my post m = dimension)

((ans)^2)/(2*9.1E-31*1.6E-19) = final ans (negative)

2: same thing but divide ans^2 by 1.6E-19 instead (this didn't work, still working on a solution)

3: 2*L (given) / E-9 = ans (neg)

4: KE = ((h^2)*(n^2))/(8*m*L^2) = ans / 1.6E-13 = ans in Mev (positive)

m = mass given in problem

h = 6.6E-34

n = quantum number

L = Given Width

these are all just other people's explanations organized more clearly, if someone could post a CLEAR description of #2 please do so

1: (h/2*pi*m) m is the number they give you, the dimension (in my post m = dimension)

((ans)^2)/(2*9.1E-31*1.6E-19) = final ans (negative)

2: same thing but divide ans^2 by 1.6E-19 instead (this didn't work, still working on a solution)

3: 2*L (given) / E-9 = ans (neg)

4: KE = ((h^2)*(n^2))/(8*m*L^2) = ans / 1.6E-13 = ans in Mev (positive)

m = mass given in problem

h = 6.6E-34

n = quantum number

L = Given Width

these are all just other people's explanations organized more clearly, if someone could post a CLEAR description of #2 please do so

**Leland**- Guest

## question 2

Can someone please help with number 2 this is the only one I cant figure out and I have been working on this since yesterday. PLEASE HELP?????

**sjames**- Guest

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