Maple TA 26_2
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Maple TA 26_2
1) the # given (pos)
2) havent figure that out..
3) mu*B*cos(degrees given)=ans (pos)
4) the # given (neg)
Can someone pls post how to solve Question #2
2) havent figure that out..
3) mu*B*cos(degrees given)=ans (pos)
4) the # given (neg)
Can someone pls post how to solve Question #2
Guest001 Guest
number 2
for number 2
negative
e^(given a * given x)
then square that
For Question 3 though, i keep trying
(magnetic moment * magnetic field * cos(given angle))
and i still am not getting the answer =/
negative
e^(given a * given x)
then square that
For Question 3 though, i keep trying
(magnetic moment * magnetic field * cos(given angle))
and i still am not getting the answer =/
:) Guest
number 3
okies sorry for so many posts..
but i see now, you have to set your calculator to radians and after that equation, divide by (1.6x10^19)
and ALSO my answer was negative.
cheers
but i see now, you have to set your calculator to radians and after that equation, divide by (1.6x10^19)
and ALSO my answer was negative.
cheers
:) Guest
Question number THree aid
You should not put your calculator in radians. Leave it in DEG.
Do:
(magnetic moment * magnetic field * cos(given angle))
Then divide what you get by 1.6E19
Do:
(magnetic moment * magnetic field * cos(given angle))
Then divide what you get by 1.6E19
Big Boy Guest
Number 4
Number 1 Obv is 2
Number 4 ABSolutely Clueless...Can anyone help me with this one? Greatly appreciate it!!!
Number 4 ABSolutely Clueless...Can anyone help me with this one? Greatly appreciate it!!!
Money23 Guest
Re: Maple TA 26_2
Firstly, I get money. Secondly, question four requires that you haven't wasted all of your brain cells away since freshman gen chem.
Principle quantum number = n = 1,2,3,4...
Azimuthal Quant. # = l = 0,1,2,... n1
Therefore for principle quantum number 3, l = 0,1,2 and there are therefore three predicted subshell or orbital shapes, the s, p and d shells.
Principle quantum number = n = 1,2,3,4...
Azimuthal Quant. # = l = 0,1,2,... n1
Therefore for principle quantum number 3, l = 0,1,2 and there are therefore three predicted subshell or orbital shapes, the s, p and d shells.
CMONEY Guest
#3  got it!!
so for # 3 the above formula is correct, but most of you who are not getting it is probably because you are not seeing the * 10^24 in for the magnetic moment number.. its easy to miss since its in the left corner of the second line...
and no need to change to radians..even if you get a negative number, the answer is pos.
and no need to change to radians..even if you get a negative number, the answer is pos.
PHy Guest
Question #2
i cant seem to get Question#2..i used the equation above but it is not working ..
woo Guest
number 2
could someone please explain the logic/ breakdown of the question. I am really confused by the question itself. i get they are looking for a ration but could some one break it down for me? greatly appreciated!!!!
quantums Guest
#3
if ur questions stated the angle in degrees set calculator to degrees, if radians then set to radians and then follow the other guys directions for #3
gamblerz Guest
QUESTION 2
CAN SOMEONE PLS POST WHAT THEY DID FOR QUESTION NUMBER TWO..THATS ALL I NEED AND IVE BEEN WORKING ON IT FOR A WHILE NOW.
Guest001 Guest
Question 2
this is what i understand from it (please correct me if I'm wrong!)
based on Slide 14: probability to observe particle at location x = (psi(x))^2
psi(x) = e^(a*x)
ratio:
psi(x) = (e^(a given * x given))^2 / (e^(a given * 0))^2
e^(a given * 0) = 1. Therefore, the ratio is just (e^(a given * x given))^2
hope that helps
based on Slide 14: probability to observe particle at location x = (psi(x))^2
psi(x) = e^(a*x)
ratio:
psi(x) = (e^(a given * x given))^2 / (e^(a given * 0))^2
e^(a given * 0) = 1. Therefore, the ratio is just (e^(a given * x given))^2
hope that helps
an0n Guest
Question 2 continued
ratio:psi(x) =(e^(a given * x given))^2 / (e^(a given * 0))^2
ignore the crossed out part
remember, answer is negative, as posted earlier by someone else
an0n Guest
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