# Maple TA 26_2

## Maple TA 26_2

1) the # given (pos)

2) havent figure that out..

3) mu*B*cos(degrees given)=ans (pos)

4) the # given (neg)

Can someone pls post how to solve Question #2

2) havent figure that out..

3) mu*B*cos(degrees given)=ans (pos)

4) the # given (neg)

Can someone pls post how to solve Question #2

**Guest001**- Guest

## number 2

for number 2

negative

e^-(given a * given x)

then square that

For Question 3 though, i keep trying

-(magnetic moment * magnetic field * cos(given angle))

and i still am not getting the answer =/

negative

e^-(given a * given x)

then square that

For Question 3 though, i keep trying

-(magnetic moment * magnetic field * cos(given angle))

and i still am not getting the answer =/

**:)**- Guest

## number 3

okies sorry for so many posts..

but i see now, you have to set your calculator to radians and after that equation, divide by (1.6x10^-19)

and ALSO my answer was negative.

cheers

but i see now, you have to set your calculator to radians and after that equation, divide by (1.6x10^-19)

and ALSO my answer was negative.

cheers

**:)**- Guest

## Question number THree aid

You should not put your calculator in radians. Leave it in DEG.

Do:

(magnetic moment * magnetic field * cos(given angle))

Then divide what you get by 1.6E-19

Do:

(magnetic moment * magnetic field * cos(given angle))

Then divide what you get by 1.6E-19

**Big Boy**- Guest

## Number 4

Number 1- Obv is 2

Number 4- ABSolutely Clueless...Can anyone help me with this one? Greatly appreciate it!!!

Number 4- ABSolutely Clueless...Can anyone help me with this one? Greatly appreciate it!!!

**Money23**- Guest

## Re: Maple TA 26_2

Firstly, I get money. Secondly, question four requires that you haven't wasted all of your brain cells away since freshman gen chem.

Principle quantum number = n = 1,2,3,4...

Azimuthal Quant. # = l = 0,1,2,... n-1

Therefore for principle quantum number 3, l = 0,1,2 and there are therefore three predicted subshell or orbital shapes, the s, p and d shells.

Principle quantum number = n = 1,2,3,4...

Azimuthal Quant. # = l = 0,1,2,... n-1

Therefore for principle quantum number 3, l = 0,1,2 and there are therefore three predicted subshell or orbital shapes, the s, p and d shells.

**CMONEY**- Guest

## #3 -- got it!!

so for # 3 the above formula is correct, but most of you who are not getting it is probably because you are not seeing the * 10^-24 in for the magnetic moment number.. its easy to miss since its in the left corner of the second line...

and no need to change to radians..even if you get a negative number, the answer is pos.

and no need to change to radians..even if you get a negative number, the answer is pos.

**PHy**- Guest

## Question #2

i cant seem to get Question#2..i used the equation above but it is not working ..

**woo**- Guest

## number 2

could someone please explain the logic/ breakdown of the question. I am really confused by the question itself. i get they are looking for a ration but could some one break it down for me? greatly appreciated!!!!

**quantums**- Guest

## #3

if ur questions stated the angle in degrees set calculator to degrees, if radians then set to radians and then follow the other guys directions for #3

**gamblerz**- Guest

## QUESTION 2

CAN SOMEONE PLS POST WHAT THEY DID FOR QUESTION NUMBER TWO..THATS ALL I NEED AND IVE BEEN WORKING ON IT FOR A WHILE NOW.

**Guest001**- Guest

## Question 2

this is what i understand from it (please correct me if I'm wrong!)

based on Slide 14: probability to observe particle at location x = (psi(x))^2

psi(x) = e^-(a*x)

ratio:

psi(x) = (e^-(a given * x given))^2 / (e^-(a given * 0))^2

e^-(a given * 0) = 1. Therefore, the ratio is just (e^-(a given * x given))^2

hope that helps

based on Slide 14: probability to observe particle at location x = (psi(x))^2

psi(x) = e^-(a*x)

ratio:

psi(x) = (e^-(a given * x given))^2 / (e^-(a given * 0))^2

e^-(a given * 0) = 1. Therefore, the ratio is just (e^-(a given * x given))^2

hope that helps

**an0n**- Guest

## Question 2 continued

ratio:~~psi(x) =~~(e^-(a given * x given))^2 / (e^-(a given * 0))^2

ignore the crossed out part

remember, answer is negative, as posted earlier by someone else

**an0n**- Guest

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