Ch 8.1 Help

Go down

Ch 8.1 Help

Post  Guest01 on Tue Oct 14, 2008 9:05 pm

Question 1
A disk turns with an average angular velocity of 0.4173 rad/s. Through which angle in degrees does the disk turn in 2.613 sec (see sheet 3)? Indicate with a negative (positive) sign whether a point on the disk at larger distance r from the center of rotation moves faster (slower) than a point at smaller distance r from the center.

How to Solve:
(Answer is _______)

ω = (ΔΘ)/(Δt)

Question 2
A point marked at the edge of a rotating disk which has a radius of 34.12 cm moves a distance of 9.562 m in 1.294 minutes. What is the average angular velocity of the disk (in SI units) (see sheet 4)? Indicate with a negative (positive) sign whether you can (cannot) use the same expression you used above to relate the instantaneous angular velocity and the instantaneous tangential velocity to each other.

How to Solve:
(Answer is Negative)

ω = v/r

To find our velocity just divide the seconds into the meters. Before we do that we have to convert those minutes into seconds. To do this multiply by 60.
timeseconds = 1.294 minutes*60
timeseconds = 77.64.

Now divide this into our meters
v = meters/seconds
v = 9.562/77.64
v = 0.1232

Convert your radius into meters
34.12cm*100 = 0.3412m

Now we can find the angular velocity (ω)
ω = v/r
ω = 0.1232/0.3412
ω =
Spoiler:
0.3609559

Question 3
A wheel with a 0.2772 meter radius, initially at rest, rolls down an incline and reaches after 5.885 seconds a linear velocity of 2.087 m/s. What is the angular acceleration of the wheel (see sheet 5 and the beginning of 34 where rolling is explained)? Indicate with a positive (negative) sign whether the tangential velocity of a point on the rim of the wheel is the same as (different from) the linear velocity of the wheel.

How to Solve:
(Answer is Positive)

α = a/r

Let's find our acceleration ([i]a[i]) whish is equal to velocity divided by the change in time (v/t). Just divide your velocity by the seconds that have passed
a = 2.087/5.885
a = 0.35463

Now we just divide by our radius,
α = 0.35463/0.2772
α =
Spoiler:
1.27933


Question 4
The constant tangential acceleration of a point at the edge of a rotating disk with a 28.2 m radius is 1.1898 m/s2. If the disk starts out with 21.58 rpm (see sheet 10 for "rpm") what is the angular velocity after 4 seconds (see sheet 5,7,10)? Indicate with a positive (negative) sign whether the initial angular velocity is (is not) given in SI units.

How to Solve:
(Answer is _______)





ΘΔπ√ωα

All I've really done so far.

Guest01

Posts : 133
Join date : 2008-09-19

View user profile

Back to top Go down

Re: Ch 8.1 Help

Post  thb1026 on Tue Oct 14, 2008 11:44 pm

for number one im having problems, i know that's the equatrion but do we have to use tan-1 anywhere? how do u calculate the exact angle?

thb1026

Posts : 8
Join date : 2008-09-27

View user profile

Back to top Go down

Re: Ch 8.1 Help

Post  alogon on Thu Oct 16, 2008 1:28 pm

You can look at angular motion (on a circle) and linear motion in a one-to-one correspondence. x->Θ, v->w, F->torque, et cetera. The units difference between angular motion and linear motion comes from what sort of "distance" you're measuring. For linear motion we use meter sticks, which gives us lengths of meters, and velocities of meters per second. We measure angles in terms of degrees or radians. A full circle has 360 degrees or two pi radians of curve, which is why the trigonometric functions are periodic on a two pi basis. from 360=2(pi) you can convert between radians and degrees at will.

The first question is really asking you to view the distance = (rate)(time) in view of angular motion, and then make a connection between the linear velocity and the angular velocity of a point on the disc. The relation v=(r)(w), where r is the distance of the point from the axis of rotation, should help you with the second part of the question.

alogon
Guest


Back to top Go down

questions 1 and 4

Post  hwilson on Thu Oct 16, 2008 2:03 pm

I still can't get 1 and 4 anyone know how to do those?

hwilson
Guest


Back to top Go down

1 and 4

Post  guest22 on Fri Oct 17, 2008 12:11 pm

can someone please help with 1 and 4?

guest22
Guest


Back to top Go down

Re: Ch 8.1 Help

Post  Question on Fri Oct 17, 2008 8:07 pm

can someone please post the equation needed for #$ because the one posted previously is not clear as to what to do.

thanks

Question
Guest


Back to top Go down

8.1 Question #4

Post  Guest 0. on Fri Oct 17, 2008 8:10 pm

i dont really understand the equation used for question #4,can someone please repost the equation that i can used for question 4.

Guest 0.
Guest


Back to top Go down

Questions 1 and 4

Post  sedwards on Sat Oct 18, 2008 12:03 pm

If anyone could please help with number 1 and number 4 I keep getting them wrong.

sedwards
Guest


Back to top Go down

Re: Ch 8.1 Help

Post  Question on Sat Oct 18, 2008 2:08 pm

Question 1:
A disk turns with an average angular velocity of 0.8273 rad/s. Through which angle in degrees does the disk turn in 4.46 sec (see sheet 3)? Indicate with a negative (positive) sign whether a point on the disk at larger distance r from the center of rotation moves faster (slower) than a point at smaller distance r from the center.

How to Solve:
Answer is NEGATIVE

First, convert the radians/sec into degrees/sec
.8273 rad/s * (1/((2pi)/(360)) = 47.4008 deg/sec
Then you do 47.4008 deg/sec * 4.46 sec = 211.407

And that is your answer

Question 4:
The constant tangential acceleration of a point at the edge of a rotating disk with a 29.7 m radius is 0.956 m/s2. If the disk starts out with 22.25 rpm (see sheet 10 for "rpm") what is the angular velocity after 4 seconds (see sheet 5,7,10)? Indicate with a positive (negative) sign whether the initial angular velocity is (is not) given in SI units.

How to Solve:
Answer is NEGATIVE

angular acc = a/r
angular acc = .956/29.7 = .03218
22.25RPM * (2pi)/(60) = 2.330014
w = 2.330014 + .03218 (4) <- where 4 is time = 2.458 which is your answer

good luck!

Question
Guest


Back to top Go down

Re: Ch 8.1 Help

Post  guest07 on Sun Oct 19, 2008 10:40 pm

I did exactly that for number 1 and its still incorrect

guest07
Guest


Back to top Go down

Does anyone Know how to figure out number 4 ??

Post  BGGirl on Sun Oct 19, 2008 11:29 pm

affraid confused I tried to figure out number 4 and labeled it positive and negative and am still getting the wrong answers and I am pretty sure I did the calculations correctly any insite?


THankS !

BGGirl

Posts : 6
Join date : 2008-09-21

View user profile

Back to top Go down

Re: Ch 8.1 Help

Post  Guest01 on Sun Oct 19, 2008 11:46 pm

Post your calculations, you both are probably messing up somewhere in converting wrong.

For question 1 it should be rad/s * 1/(2pi/360) [that is calculate 2*pi divided by 360, then divide that into 1.

For question 4, after you find your angular acc times that by 4. and then add that to your converted RPM. For the converted RPM it's 2*pi and divide that by 60 and take that and multiply it by your given RPM for your converted RPM

Guest01

Posts : 133
Join date : 2008-09-19

View user profile

Back to top Go down

Re: Ch 8.1 Help

Post  Sponsored content


Sponsored content


Back to top Go down

Back to top


 
Permissions in this forum:
You cannot reply to topics in this forum