Lab Quiz 6
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q2
Just make sure the radius is in meters and the mass is in kg. and do .5*m*r^2 ...if that doesnt work again post your question
k Guest
Re: Lab Quiz 6
why we use I=mg/(alpha fric+alpha) instead of the given formular I=mr(gra)/(afr+a)??
student Guest
Re: Lab Quiz 6
I'm almost positive my calculations are correct, but Maple keeps saying it's wrong, here are my numbers and calculations:
mass = .2 kg
radius = 2.5 cm = .025 m
% = 1.25
a = 0.268
a_{f} = 0.177
so
(1.25/100)*.025 = 0.0003125
(.2*9.81)/(.177+.268)
1.962/.445
= 4.4089888
4.4089888*0.0003125
= 0.001377809
mass = .2 kg
radius = 2.5 cm = .025 m
% = 1.25
a = 0.268
a_{f} = 0.177
so
(1.25/100)*.025 = 0.0003125
(.2*9.81)/(.177+.268)
1.962/.445
= 4.4089888
4.4089888*0.0003125
= 0.001377809
Guest01 Posts : 133
Join date : 20080919
Re: Lab Quiz 6
Okay I know those calculations are correct but for some reason Maple TA did not like it. I took it again and it worked.
Guest01 Posts : 133
Join date : 20080919
question 3
this is the exact thing i did and got it right.
I = mr(g(radius*a)) /(afric+a) .... the absolute sign in the denominator is a must dont forget it and dont forget to convert the radius to meters.
then simply divide your % for radius by 100.
then multiply that by what youu got for I.
I = mr(g(radius*a)) /(afric+a) .... the absolute sign in the denominator is a must dont forget it and dont forget to convert the radius to meters.
then simply divide your % for radius by 100.
then multiply that by what youu got for I.
helpful Guest
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