Maple TA Quiz 18-2
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Maple TA Quiz 18-2
Question 1: Rearrange the equation F=I*l*B*sin0. Solve by plugging into the equation I=F/(B*l*sin0).
I = Current
l = Wire Length
B = Magnetic Field
F = Magnetic Force on the Wire
0 = Angle made with the magnetic field (and thereby paper plane - horizonal positive axis)
Answer is negative.
I = Current
l = Wire Length
B = Magnetic Field
F = Magnetic Force on the Wire
Answer is negative.
helping- Guest
Re: Maple TA Quiz 18-2
Question 2: Solve by plugging into the equation t=I*A*B*sin0 and then multiplying the answer by 10 (since there are ten wire loops, not only one). Don't forget to convert cm^2 to standard units (1cm^2=.0001m^2).
t = Torque
I = Current
B = Magnetic Field
A = Cross Sectional Area of one of the Wire Loops
0 = Angle made with the magnetic field (horizonal positive axis)
Answer is positive.
t = Torque
I = Current
B = Magnetic Field
A = Cross Sectional Area of one of the Wire Loops
0 = Angle made with the magnetic field (horizonal positive axis)
Answer is positive.
helping- Guest
Re: Maple TA Quiz 18-2
Question 3: Rearrange the equation B=2*pi*k(prime)*(I/r). Solve by plugging into the equation r=(2*pi*k(prime)*I)/B.
I = Current
B = Magnetic Field
r = Radius of the Loop
k(prime) = 10^-7 (constant)
Answer is positive.
I = Current
B = Magnetic Field
r = Radius of the Loop
k(prime) = 10^-7 (constant)
Answer is positive.
helping- Guest
Re: Maple TA Quiz 18-2
Question 4: Solve by plugging into the equation B=4*pi*k(prime)*I*n. n is calculated by dividing the number of turns by the length (N/l). Don't forget to convert cm to standard units (1cm = .01m).
I = Current
l = Solenoid Length
N = # of Turns
k(prime) = 10^-7 (constant)
n = # of Turns Per Unit Length
B = Magnetic Field inside the Solenoid
Answer is negative.
I = Current
l = Solenoid Length
N = # of Turns
k(prime) = 10^-7 (constant)
n = # of Turns Per Unit Length
B = Magnetic Field inside the Solenoid
Answer is negative.
helping- Guest
Maple 18_2
unfortunately, i think they might have changed the quiz on us... my quiz is actually computational... and not at all like the posted help.
For Example my Question 1 reads:
A current carrying 16.63 cm long wire lies in the paper plane. The current direction makes an angle of 54.55o with a 0.15 T magnetic field which lies in the paper plane and points along the horizontal positive x-axis. What is the current when the magnetic force on the wire is 0.03026 N (see sheet 15) ? Indicate with a positive (negative) sign whether the magnetic force lies in the (is perpendicular to) the paper plane.[b]
For Example my Question 1 reads:
A current carrying 16.63 cm long wire lies in the paper plane. The current direction makes an angle of 54.55o with a 0.15 T magnetic field which lies in the paper plane and points along the horizontal positive x-axis. What is the current when the magnetic force on the wire is 0.03026 N (see sheet 15) ? Indicate with a positive (negative) sign whether the magnetic force lies in the (is perpendicular to) the paper plane.[b]
phygirl- Guest
question number 4
I can't seem to get the correct answer to number 4, although I am doing it the exact way as posted. Does anything else have to be converted besides meters?
Stef- Guest
Re: Maple TA Quiz 18-2
for some reason its not working for me either 18_2#3 , is there this k prime or ? causing it could someone shed some light here
gr8luck- Posts : 5
Join date : 2008-09-18
Re: Maple TA Quiz 18-2
The reason they are not working for you is because your in the wrong mode....make sure your calculator is set to degrees NOT radian!
Duh!- Guest
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