Maple TA 25_2
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Maple TA 25_2
1. A photon has a wavelength of 655.2 nm. What is the photon momentum in eV/c (sheet 14). Indicate with a positive (negative) sign whether the momentum unit quoted is (not) an SI unit.
= (6.64E34)*(3E8)
=(1.98E25)
THEN
=(1.98E25)/(655.2E9)
=(3.02198E19)
THEN
=(3.02198E19)/(1.6E19)
=1.88874
Reasoning: First step is to get the value for value for (hc) then you divide by the wavelength to get the value of E, and lastly divide by 1.6E19 to get the value in terms of eV instead of Joules.
= (6.64E34)*(3E8)
=(1.98E25)
THEN
=(1.98E25)/(655.2E9)
=(3.02198E19)
THEN
=(3.02198E19)/(1.6E19)
=1.88874
Reasoning: First step is to get the value for value for (hc) then you divide by the wavelength to get the value of E, and lastly divide by 1.6E19 to get the value in terms of eV instead of Joules.
User X Guest
Maple TA 25_2
4. An atom makes a transition from its current state into an energy state which is 2.067 eV higher. Indicate with a negative (positive) sign whether a photon is emitted (absorbed) by the atom and calculate the wavelength of the photon (sheet 32).
=(6.64E34)*(3E8)
=(1.992E25)
THEN
=(1.992E25)/(1.6E19)
=(1.245E6)
THEN
=(1.245E6)/(2.067)
=(6.02322E7)(POSITIVE)
=(6.64E34)*(3E8)
=(1.992E25)
THEN
=(1.992E25)/(1.6E19)
=(1.245E6)
THEN
=(1.245E6)/(2.067)
=(6.02322E7)(POSITIVE)
User X Guest
Maple TA 25_2
2. A 17.37 KeV photon scatters off an electron (Compton Effect) and has a wavelength of 0.099 nm after the collision. What is the kinetic energy of the recoil electron in KeV (sheet 1518) ? Indicate with a positive (negative) sign whether the electron kinetic energy is of the same order of magnitude as (considerably smaller than) the electron rest energy.
=((6.64E34)*(3E8))/(.099E9)
=(2.01212E15)
THEN
=(2.01212E15)/(1.6E19)
=(12575.8eV)>12.5758 KeV (in terms of KeV is what the question is asking for)
THEN
=(17.37)  (12.5758)
= (4.7942)(NEGATIVE)
Reasoning: You need to first solve to get "E", and then you divide that answer by 1.6E19 to convert into eV, and then divide by 1000 to convert from eV to KeV. Then to find the kinetic energy of the recall electron, you subtract the two.
=((6.64E34)*(3E8))/(.099E9)
=(2.01212E15)
THEN
=(2.01212E15)/(1.6E19)
=(12575.8eV)>12.5758 KeV (in terms of KeV is what the question is asking for)
THEN
=(17.37)  (12.5758)
= (4.7942)(NEGATIVE)
Reasoning: You need to first solve to get "E", and then you divide that answer by 1.6E19 to convert into eV, and then divide by 1000 to convert from eV to KeV. Then to find the kinetic energy of the recall electron, you subtract the two.
User X Guest
#3
first divide theta by 2 and convert the d into meters
lambda = (2dsin(theta))/n
second p = h/lambda from above
third KE= (p from above)^2/(2*9.1*10^31)
forth convert to eV KE from above /(1.6*10^19)
lambda = (2dsin(theta))/n
second p = h/lambda from above
third KE= (p from above)^2/(2*9.1*10^31)
forth convert to eV KE from above /(1.6*10^19)
supr mo Guest
Question 3
What is n in the first formula provided?
An electron beam scattered off a crystal at a scattering angle of 26.99 0 produces a second order diffraction maximum. What is the kinetic energy (nonrelativistically) of the electrons in eV if the crystal plane spacing is 0.2637 nm (sheet 22,27) ? Indicate with a positive (negative) sign whether here the particle (wave) property of the electron becomes evident.
what i did so far was 2*.2637E9= 5.274E10*sin(13.495)/n, but what is n?
An electron beam scattered off a crystal at a scattering angle of 26.99 0 produces a second order diffraction maximum. What is the kinetic energy (nonrelativistically) of the electrons in eV if the crystal plane spacing is 0.2637 nm (sheet 22,27) ? Indicate with a positive (negative) sign whether here the particle (wave) property of the electron becomes evident.
what i did so far was 2*.2637E9= 5.274E10*sin(13.495)/n, but what is n?
Guest786 Guest
question 3
I am having trouble with that one as well if someone could post a more detailed description of how to solve it I would appreciate it. Thanks.
sck105 Guest
sck105?
sck105....what do you mean by more details? i thought the details above by userx was very detailed lol.
phyfrk Guest
Maple TA 25_2
Here's a full description on question 3.
An electron beam scattered off a crystal at a scattering angle of 27.9 0 produces a second order diffraction maximum. What is the kinetic energy (nonrelativistically) of the electrons in eV if the crystal plane spacing is 0.2926 nm (sheet 22,27) ? Indicate with a positive (negative) sign whether here the particle (wave) property of the electron becomes evident.
=(27.9)/2
=13.95
THEN
=(2)*(.2926E9)*sin(13.95)
=(4.70665E24)/2
=7.05386E11
THEN
=(6.64E34)/(7.05386E11)
=9.41329E29
THEN
=(9.41329E29)^2
=8.861E47
THEN
=(8.861E47)/(2*9.1E31)
=4.86868E17
THEN
=(4.86868E17)/(1.6E19)
=304.293 (NEGATIVE)
An electron beam scattered off a crystal at a scattering angle of 27.9 0 produces a second order diffraction maximum. What is the kinetic energy (nonrelativistically) of the electrons in eV if the crystal plane spacing is 0.2926 nm (sheet 22,27) ? Indicate with a positive (negative) sign whether here the particle (wave) property of the electron becomes evident.
=(27.9)/2
=13.95
THEN
=(2)*(.2926E9)*sin(13.95)
=(4.70665E24)/2
=7.05386E11
THEN
=(6.64E34)/(7.05386E11)
=9.41329E29
THEN
=(9.41329E29)^2
=8.861E47
THEN
=(8.861E47)/(2*9.1E31)
=4.86868E17
THEN
=(4.86868E17)/(1.6E19)
=304.293 (NEGATIVE)
User X Guest
3
I am still getting it wrong
my numbers were 34.84 and .15nm
my final answer came to 75.10 but it says wrong
can someone help me
my numbers were 34.84 and .15nm
my final answer came to 75.10 but it says wrong
can someone help me
:( Guest
:(
You are very close My answer is in the 74_._ _ (that's seven hundred forty something point something)
To start you off:(2*0.15*10^9*sin(17.42))/2 = 4.49061*10^11 (wavelength)
(6.63*10^34)/(4.49061*10^11) = (P or the momentum) follow all of the other posts to get you to your answer.
Gook luck!!!!
To start you off:(2*0.15*10^9*sin(17.42))/2 = 4.49061*10^11 (wavelength)
(6.63*10^34)/(4.49061*10^11) = (P or the momentum) follow all of the other posts to get you to your answer.
Gook luck!!!!
uer mo Guest
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