Lab 10 prep

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Lab 10 prep Empty Lab 10 prep

Post  Physics on Sat Apr 25, 2009 1:58 pm

Question 1:

They give you N=100, and say the absolute error is sqrt(N) so absolute error = 10.
By definition we know that absolute error is the relative error times the value (N), so to find relative error you just now divide by your value N(100) and you get .1 . If you complete the same procedure for the next two parts you get 31.62 and .03162.

Question 2:

All I have so far is:
If x is in meters what are the units of the absorption constant ? 1/m

Question 3:

All I have so far is:
In this equation what are the units of lambda if t is in seconds? 1/s

Physics
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Lab 10 prep Empty Q2 +3

Post  student7 on Sat Apr 25, 2009 7:58 pm

N=N_0*e^(-lambda*x)
we want only 0.01 (or 1%) left so that is what N =
N_0 = 1 (or 100%) which is what we start out with so

0.01/1 = e^-lambda*90 (given this #)
ln (0.01)/90=lambda

Q 3
second part
ln(2)/lambda

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Lab 10 prep Empty question #2 and 3

Post  Guest001 on Sun Apr 26, 2009 7:29 am

did anyone get Question #3 and the rest of Question #2?

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Lab 10 prep Empty question 2

Post  sck105 on Sun Apr 26, 2009 11:50 am

I am having trouble with the rest of question 2 as well can someone please help?

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Lab 10 prep Empty Re: Lab 10 prep

Post  guestttt on Sun Apr 26, 2009 12:20 pm

rest of Q2:

thickness would have to be .0511685576 m

23.66205057% of rays would be blocked
just use the formula: N=N_o*e^-lambda(x). the new thickness is .003m, lambda is still 90, N_o is 1, and you're looking for N. solve for that, you get that N=.7633794943, but that's the percent that's allowed through, so multiply by 100 for the percentage then subtract from 100 to get 23.66205057

Q3:

units are 1/s
lambda is just ln(2)/half life given in minutes
N=N_o*e^-lambda(t) .. ln(.01)/answer from above question

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Lab 10 prep Empty Question #3

Post  Guest 00 on Sun Apr 26, 2009 4:30 pm

what is the equation for the half life in terms of( lambda) in Question #3?

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Lab 10 prep Empty half life is. + question 3 last part?

Post  :) on Mon Apr 27, 2009 1:11 am

ln(2)/lambda


did anyone get the very last question?

how long would it take for 1 percent?

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Lab 10 prep Empty lab 10 q 3

Post  manny on Mon Apr 27, 2009 8:13 am

question 3 :


.266 (you do ln2/(2.6min x 60 sec)



17.31 ( ln100/( .266)

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Lab 10 prep Empty Question #3-part 2

Post  guest001 on Mon Apr 27, 2009 9:52 am

in question#3, do anyone know the equation for half life in terms of lambda....this is question #3-part 2?

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