Lab Report 5
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Q7
Q7
equation 7 for "error and uncertainty" gives me sqrt((.002/vi)^2+(.001/.165)^2)=.0111 for the correct error. Then my incorrect error is (.002/vi)=.0094. Then when i do ((correct-incorrect)/correct)*100 to get the ratio my ratio is ~16%. any ideas to what i am doing wrong?
equation 7 for "error and uncertainty" gives me sqrt((.002/vi)^2+(.001/.165)^2)=.0111 for the correct error. Then my incorrect error is (.002/vi)=.0094. Then when i do ((correct-incorrect)/correct)*100 to get the ratio my ratio is ~16%. any ideas to what i am doing wrong?
raven- Guest
Re: Lab Report 5
For Question 5
The missing image is for Δv/v which is equal to the relative error of the width. Just express the error of Δv/v in terms of width using w and Δw
Question 7
This question needs to be broken down. I forget my exact collections, although I followed one of the formulas posted previously. Our ratio is found using the formula (correct-approximate)/correct. All we are doing is finding some sort of value range, in rough terms. There is a precise number we want, we call it correct and there is also an estimated value, a round about, what we can expect value. This is represented by the word approximate in the equation. The words correct and approximate really just stand for certain formulas, one to find a precise value and the other is the estimated value.
The ratio is for the Δρ that is the momentum (interpreted as p). In Question 6 we found the formula to find the error of momentum. Question 6 represents the correct value because it is a bit more precise using more numbers. The question tells us that the approximate value isΔρ but not as precise. For the approximate value we can ignore the Δm/m because it is negligible.
So what is the formula for Δρ? Then find it again, but with out using the Δm/m and use these as your values for the (correct-approximate)/correct formula to get a final ratio.
Also you do not need to multiple by 100. It is not a percentile error, it is a ratio, so try that value without the x 100%.
Author's Character List
Δπ√αθΨΛδΓωχσρβ
The missing image is for Δv/v which is equal to the relative error of the width. Just express the error of Δv/v in terms of width using w and Δw
Question 7
This question needs to be broken down. I forget my exact collections, although I followed one of the formulas posted previously. Our ratio is found using the formula (correct-approximate)/correct. All we are doing is finding some sort of value range, in rough terms. There is a precise number we want, we call it correct and there is also an estimated value, a round about, what we can expect value. This is represented by the word approximate in the equation. The words correct and approximate really just stand for certain formulas, one to find a precise value and the other is the estimated value.
The ratio is for the Δρ that is the momentum (interpreted as p). In Question 6 we found the formula to find the error of momentum. Question 6 represents the correct value because it is a bit more precise using more numbers. The question tells us that the approximate value isΔρ but not as precise. For the approximate value we can ignore the Δm/m because it is negligible.
So what is the formula for Δρ? Then find it again, but with out using the Δm/m and use these as your values for the (correct-approximate)/correct formula to get a final ratio.
Also you do not need to multiple by 100. It is not a percentile error, it is a ratio, so try that value without the x 100%.
Author's Character List
Δπ√αθΨΛδΓωχσρβ
Guest01- Posts : 133
Join date : 2008-09-19
number 7
for #7 i understand the formula that we use but which w do we use (small or big?) and which v's or p's?
confused- Guest
Re: Lab Report 5
I forget which ones I used, however I'm sure if you are consistent, that is use just the big mass and the big width and the big momentum that should be good.
Guest01- Posts : 133
Join date : 2008-09-19
Question 9
For Vi prime, I divided my Ws, in my case 0.0458 m by Ti prime, in my case 0.3957 s, for an answer of .1157 m/s. Of course, MapleTA isn't accepting my answer. Any suggestions on what am doing wrong/how I can get MapleTA to accept my answer?
LMS- Guest
Question 29
It is asking what happens in elastic and inelastic collisions both before (ρ) and after the collision (ρ). From your observations, or rather ideal observations, what happens in such collisions?
Guest01- Posts : 133
Join date : 2008-09-19
Re: Lab Report 5
For Question 24 let's figure out two things. Since we are finding ρ, what is the formula for it, i.e. how do we find it?
To find Deltaρ we use Equation 7 from E&U. What does that equation look like? Can you put that equation into terms which express ρ? Meaning what values would you use in the equation that you used for ρ?
We'll take it step by step of need be, get back to me, let me know if you got it or are still confused.
To find Deltaρ we use Equation 7 from E&U. What does that equation look like? Can you put that equation into terms which express ρ? Meaning what values would you use in the equation that you used for ρ?
We'll take it step by step of need be, get back to me, let me know if you got it or are still confused.
Guest01- Posts : 133
Join date : 2008-09-19
Re: Lab Report 5
That's it, that's the formula!
Just remember to multiply ρ after the sqrt(...).
As for which mass to use, think of it this way, the momentum is the object that is moving. Since the big glider is moving, only that has momentum and it is pre-collision, notated by ρ. In the inelastic collision, bith the object stick together, correct? so the momentum will be both masses added since it essentially becomes one big glider.
So yes you are using the total.
Just remember to multiply ρ after the sqrt(...).
As for which mass to use, think of it this way, the momentum is the object that is moving. Since the big glider is moving, only that has momentum and it is pre-collision, notated by ρ. In the inelastic collision, bith the object stick together, correct? so the momentum will be both masses added since it essentially becomes one big glider.
So yes you are using the total.
Guest01- Posts : 133
Join date : 2008-09-19
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