Maple TA Quiz 201
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Maple TA Quiz 201
Question 1: (Value in microF)*(Value in kiloOhm)*(10^3)
Answer is negative.
Answer is negative.
helping Guest
Re: Maple TA Quiz 201
Question 4: (Value in V)/(e^((Value in ms*10^3)/(Value in kiliOhm*Value in nF*10^6)))
Answer is negative.
Answer is negative.
helping Guest
Re: Maple TA Quiz 201
Question 2: ((Value in kV*10^3)*(((Value in s)/(Value in mF*Value in kOhm))))/(Value in kOhm*10^3)
Correct answer should be around 0.05.
Answer is negative.
Correct answer should be around 0.05.
Answer is negative.
helping Guest
Re: Maple TA Quiz 201
Question 3: ln(1(% provided/100))*(Value in microseconds)*10^6
Answer is positive.
Sorry about the wait for these two. I was a bit tired the other day and simply had a bit of trouble with these (2,3) so I left them for today.
Answer is positive.
Sorry about the wait for these two. I was a bit tired the other day and simply had a bit of trouble with these (2,3) so I left them for today.
helping Guest
question 2
I am having problems with this question, i used this equation provided above: ((Value in kV*10^3)*(((Value in s)/(Value in mF*Value in kOhm))))/(Value in kOhm*10^3) and i am still not getting it right...
What is the discharging current in an RC circuit with a 0.2589 resistor and an initial voltage of 1.645 kV across a 50 mF capacitor after 27.49 s from the begin of the discharge (see sheet 8,8',9) ? Indicate with a negative (positive) sign whether the charging and discharging current have (do not have) the same functional dependence on time.
this is what i did:
((1.645*10^3)*(((27.49)/(50*.2589))))/(.2589*10^3)
What is the discharging current in an RC circuit with a 0.2589 resistor and an initial voltage of 1.645 kV across a 50 mF capacitor after 27.49 s from the begin of the discharge (see sheet 8,8',9) ? Indicate with a negative (positive) sign whether the charging and discharging current have (do not have) the same functional dependence on time.
this is what i did:
((1.645*10^3)*(((27.49)/(50*.2589))))/(.2589*10^3)
guest786 Guest
q2
I cant figure out 2 either and I am following the method provided above anyone know how solve this question?
sjames Guest
#2 not working
hi helping. #2 is not working for me either. Could you take a shot at solving my problem for #2? I keep getting 20.96 as my answer when i do it the way you showed above but its incorrect when i put it in maple. i'd really appreciate it if you could help. thanks!
What is the discharging current in an RC circuit with a 0.1791 resistor and an initial voltage of 1.24 kV across a 50 mF capacitor after 27.11 s from the begin of the discharge (see sheet 8,8',9) ? Indicate with a negative (positive) sign whether the charging and discharging current have (do not have) the same functional dependence on time.
What is the discharging current in an RC circuit with a 0.1791 resistor and an initial voltage of 1.24 kV across a 50 mF capacitor after 27.11 s from the begin of the discharge (see sheet 8,8',9) ? Indicate with a negative (positive) sign whether the charging and discharging current have (do not have) the same functional dependence on time.
phystude Guest
Re: Maple TA Quiz 201
My mistake. I believe I left out the e^ before the  sign once you open the parentheses.
helping Guest
queston 2
followed the method above for #2 n i still don't get it >< thanks if anyone can help!
12345 Guest
Question #2
The method above should work if done properly, however, your answer will not necessarily be around 0.05. Mine was actually 0.75.
((Value in kV*10^3)*(e^(((Value in s)/(Value in mF*Value in kOhm)))/(Value in kOhm*10^3))
hope it helps!
((Value in kV*10^3)*(e^(((Value in s)/(Value in mF*Value in kOhm)))/(Value in kOhm*10^3))
hope it helps!
PHY000 Guest
question 2
use the equation Vc=Vo*e^(t/RC)
remember e is actually one of the functions on the graphing calculator such that ln(e^x) will give you x
once you solved for Vc then use the equation Vc=Ic*R
remember Vc is the voltage discharge which is what you are solving for and Vo is just the initial voltage and Ic is just the current discharged from Vc
remember e is actually one of the functions on the graphing calculator such that ln(e^x) will give you x
once you solved for Vc then use the equation Vc=Ic*R
remember Vc is the voltage discharge which is what you are solving for and Vo is just the initial voltage and Ic is just the current discharged from Vc
gamblerz Guest
#3
i still couldnt get #3 with the equation provided, my answer came out to be negative. helppp
lost Guest
20_1 #2
use equation 20.5'. This gives you voltage...then divide by the resistance they give you to get the current. FORMULA: V(given)*e^(t/RC)> then divide by R
this wor Guest
#3
the power of e is negative. So when you do ln and the e comes off....you have . Plus, ln(1%/100) is negative. Multiply the 2 and you get positive.
it works Guest
Question 3
Don't be bothered with the value of 0.05 or whatever.
I got 3.04 as my value and got it right.
I got 3.04 as my value and got it right.
123123 Guest
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