Maple TA 26_2

1) the # given (pos)
2) havent figure that out..
3) mu*B*cos(degrees given)=ans (pos)
4) the # given (neg)



Can someone pls post how to solve Question #2

for number 2

negative

e^-(given a * given x)

then square that



For Question 3 though, i keep trying

-(magnetic moment * magnetic field * cos(given angle))

and i still am not getting the answer =/

what did you mean by m in the equation?

okies sorry for so many posts..

but i see now, you have to set your calculator to radians and after that equation, divide by (1.6x10^-19)

and ALSO my answer was negative.

cheers

I'm still getting number three wrong. could someone explain again? thanks!

IS still wrong AHHH!!

You should not put your calculator in radians. Leave it in DEG.

Do:
(magnetic moment * magnetic field * cos(given angle))

Then divide what you get by 1.6E-19

Number 1- Obv is 2
Number 4- ABSolutely Clueless...Can anyone help me with this one? Greatly appreciate it!!!

i used the equation posted and it didnt work for me..pls help

Firstly, I get money. Secondly, question four requires that you haven't wasted all of your brain cells away since freshman gen chem.

Principle quantum number = n = 1,2,3,4...

Azimuthal Quant. # = l = 0,1,2,... n-1

Therefore for principle quantum number 3, l = 0,1,2 and there are therefore three predicted subshell or orbital shapes, the s, p and d shells.

so for # 3 the above formula is correct, but most of you who are not getting it is probably because you are not seeing the * 10^-24 in for the magnetic moment number.. its easy to miss since its in the left corner of the second line...
and no need to change to radians..even if you get a negative number, the answer is pos.

i cant seem to get Question#2..i used the equation above but it is not working ..

I for some reason cant get number 4 either. What is the answer pleaseeeee

could someone please explain the logic/ breakdown of the question. I am really confused by the question itself. i get they are looking for a ration but could some one break it down for me? greatly appreciated!!!!

if ur questions stated the angle in degrees set calculator to degrees, if radians then set to radians and then follow the other guys directions for #3

and for #4 so take the negative of the number n...one significant digit is enough

did anyone get #2

CAN SOMEONE PLS POST WHAT THEY DID FOR QUESTION NUMBER TWO..THATS ALL I NEED AND IVE BEEN WORKING ON IT FOR A WHILE NOW.

this is what i understand from it (please correct me if I'm wrong!)

based on Slide 14: probability to observe particle at location x = (psi(x))^2

psi(x) = e^-(a*x)

ratio:

psi(x) = (e^-(a given * x given))^2 / (e^-(a given * 0))^2

e^-(a given * 0) = 1. Therefore, the ratio is just (e^-(a given * x given))^2

hope that helps

ratio:

psi(x) = (e^-(a given * x given))^2 / (e^-(a given * 0))^2

ignore the crossed out part


remember, answer is negative, as posted earlier by someone else