# Maple TA Quiz 18-2

## Maple TA Quiz 18-2

Question 1: Rearrange the equation F=I*~~0~~. Solve by plugging into the equation I=F/(B*~~0~~).

I = Current

B = Magnetic Field

F = Magnetic Force on the Wire

~~0~~ = Angle made with the magnetic field (and thereby paper plane - horizonal positive axis)

Answer is negative.

*l**B*sin*l**sinI = Current

*l*= Wire LengthB = Magnetic Field

F = Magnetic Force on the Wire

Answer is negative.

**helping**- Guest

## Re: Maple TA Quiz 18-2

Question 2: Solve by plugging into the equation t=I*A*B*sin~~0~~ and then multiplying the answer by 10 (since there are ten wire loops, not only one). Don't forget to convert cm^2 to standard units (1cm^2=.0001m^2).

t = Torque

I = Current

B = Magnetic Field

A = Cross Sectional Area of one of the Wire Loops

0 = Angle made with the magnetic field (horizonal positive axis)

Answer is positive.

t = Torque

I = Current

B = Magnetic Field

A = Cross Sectional Area of one of the Wire Loops

0 = Angle made with the magnetic field (horizonal positive axis)

Answer is positive.

**helping**- Guest

## Re: Maple TA Quiz 18-2

Question 3: Rearrange the equation B=2*pi*k(prime)*(I/r). Solve by plugging into the equation r=(2*pi*k(prime)*I)/B.

I = Current

B = Magnetic Field

r = Radius of the Loop

k(prime) = 10^-7 (constant)

Answer is positive.

I = Current

B = Magnetic Field

r = Radius of the Loop

k(prime) = 10^-7 (constant)

Answer is positive.

**helping**- Guest

## Re: Maple TA Quiz 18-2

Question 4: Solve by plugging into the equation B=4*pi*k(prime)*I*n. n is calculated by dividing the number of turns by the length (N/

I = Current

N = # of Turns

k(prime) = 10^-7 (constant)

n = # of Turns Per Unit Length

B = Magnetic Field inside the Solenoid

Answer is negative.

*l*). Don't forget to convert cm to standard units (1cm = .01m).I = Current

*l*= Solenoid LengthN = # of Turns

k(prime) = 10^-7 (constant)

n = # of Turns Per Unit Length

B = Magnetic Field inside the Solenoid

Answer is negative.

**helping**- Guest

## Maple 18_2

unfortunately, i think they might have changed the quiz on us... my quiz is actually computational... and not at all like the posted help.

For Example my Question 1 reads:

A current carrying 16.63 cm long wire lies in the paper plane. The current direction makes an angle of 54.55o with a 0.15 T magnetic field which lies in the paper plane and points along the horizontal positive x-axis. What is the current when the magnetic force on the wire is 0.03026 N (see sheet 15) ? Indicate with a positive (negative) sign whether the magnetic force lies in the (is perpendicular to) the paper plane.[b]

For Example my Question 1 reads:

A current carrying 16.63 cm long wire lies in the paper plane. The current direction makes an angle of 54.55o with a 0.15 T magnetic field which lies in the paper plane and points along the horizontal positive x-axis. What is the current when the magnetic force on the wire is 0.03026 N (see sheet 15) ? Indicate with a positive (negative) sign whether the magnetic force lies in the (is perpendicular to) the paper plane.[b]

**phygirl**- Guest

## question number 4

I can't seem to get the correct answer to number 4, although I am doing it the exact way as posted. Does anything else have to be converted besides meters?

**Stef**- Guest

## Re: Maple TA Quiz 18-2

for some reason its not working for me either 18_2#3 , is there this k prime or ? causing it could someone shed some light here

**gr8luck**- Posts : 5

Join date : 2008-09-18

## Re: Maple TA Quiz 18-2

The reason they are not working for you is because your in the wrong mode....make sure your calculator is set to degrees NOT radian!

**Duh!**- Guest

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