Maple TA Quiz 18-2

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Maple TA Quiz 18-2

Post  helping on Mon Feb 16, 2009 10:13 pm

Question 1: Rearrange the equation F=I*l*B*sin0. Solve by plugging into the equation I=F/(B*l*sin0).

I = Current
l = Wire Length
B = Magnetic Field
F = Magnetic Force on the Wire
0 = Angle made with the magnetic field (and thereby paper plane - horizonal positive axis)

Answer is negative.

helping
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Re: Maple TA Quiz 18-2

Post  helping on Mon Feb 16, 2009 10:24 pm

Question 2: Solve by plugging into the equation t=I*A*B*sin0 and then multiplying the answer by 10 (since there are ten wire loops, not only one). Don't forget to convert cm^2 to standard units (1cm^2=.0001m^2).

t = Torque
I = Current
B = Magnetic Field
A = Cross Sectional Area of one of the Wire Loops
0 = Angle made with the magnetic field (horizonal positive axis)

Answer is positive.

helping
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Re: Maple TA Quiz 18-2

Post  helping on Mon Feb 16, 2009 10:36 pm

Question 3: Rearrange the equation B=2*pi*k(prime)*(I/r). Solve by plugging into the equation r=(2*pi*k(prime)*I)/B.

I = Current
B = Magnetic Field
r = Radius of the Loop
k(prime) = 10^-7 (constant)

Answer is positive.

helping
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Re: Maple TA Quiz 18-2

Post  helping on Mon Feb 16, 2009 10:44 pm

Question 4: Solve by plugging into the equation B=4*pi*k(prime)*I*n. n is calculated by dividing the number of turns by the length (N/l). Don't forget to convert cm to standard units (1cm = .01m).

I = Current
l = Solenoid Length
N = # of Turns
k(prime) = 10^-7 (constant)
n = # of Turns Per Unit Length
B = Magnetic Field inside the Solenoid

Answer is negative.

helping
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Re: Maple TA Quiz 18-2

Post  sck105 on Mon Feb 16, 2009 10:52 pm

Helping you are amazing!!! THANK YOU!

sck105
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Maple 18_2

Post  phygirl on Wed Feb 18, 2009 2:58 am

unfortunately, i think they might have changed the quiz on us... my quiz is actually computational... and not at all like the posted help.

For Example my Question 1 reads:

A current carrying 16.63 cm long wire lies in the paper plane. The current direction makes an angle of 54.55o with a 0.15 T magnetic field which lies in the paper plane and points along the horizontal positive x-axis. What is the current when the magnetic force on the wire is 0.03026 N (see sheet 15) ? Indicate with a positive (negative) sign whether the magnetic force lies in the (is perpendicular to) the paper plane.[b]

phygirl
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Re: Maple TA Quiz 18-2

Post  thnks! on Thu Feb 19, 2009 3:08 am

THank u soo soo much!!!! =D

thnks!
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question number 4

Post  Stef on Thu Feb 19, 2009 9:30 pm

I can't seem to get the correct answer to number 4, although I am doing it the exact way as posted. Does anything else have to be converted besides meters?

Stef
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Re: Maple TA Quiz 18-2

Post  user on Thu Feb 19, 2009 11:53 pm

none of these are working for me

user
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Re: Maple TA Quiz 18-2

Post  phent on Fri Feb 20, 2009 12:24 am

for some reasons none of these formulas posted are working for me.

phent
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Re: Maple TA Quiz 18-2

Post  Guest 87 on Fri Feb 20, 2009 2:20 am

Thanx alot helping!!!

Guest 87
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Re: Maple TA Quiz 18-2

Post  gr8luck on Fri Feb 20, 2009 2:21 pm

for some reason its not working for me either 18_2#3 , is there this k prime or ? causing it could someone shed some light here

gr8luck

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Re: Maple TA Quiz 18-2

Post  Duh! on Fri Feb 20, 2009 2:37 pm

The reason they are not working for you is because your in the wrong mode....make sure your calculator is set to degrees NOT radian!

Duh!
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Re: Maple TA Quiz 18-2

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