Maple TA 26-1 Quiz

Does anyone know how to do questions 2 and 3?

does anyone know how to do any of them at all????

You MUST go past the sheets that is stated in the question for 26_1, 2, and 3. Go through all of the lecture sheets.
To get you started on 26_1 #1
Delta P= h/(2pim) where m is given
plug answer into KE = (P)^2/92*9.1*10^-31 then convert to eV

can someone plz help with number 2 and 3?

Does anyone have any idea how to do questions 3 and 4 on this I am really struggling.....please help me????

I am really having trouble with 2 and 3 as well anyone have anything?

You are using the same equation as for number 1, but no need to divide by (2 * 9.1e-31) just divide by 1.6e-19.

Basically 2* L (given), convert to nm. Answer is negative.

Follow the problem on page 22 of the CD, your final answer will be in eV, just convert to megaeV and you get your final answer. Answer is positive.

I still cant figure out 4 can someone please help me out?

I have tried everything for number one and four can someone please post a detailed description of how they solved it????????????? pleassseee?

please someone kindly help out! I've been stuck on question 4 for a long while! thanks!

For number 4 the numbers you are getting are in J, you'd like them in MeV...the conversion is 1.609E-13J = 1 MeV. Best of luck.

Oh yea, and use the formula on Sheet 16'.

Can you explain how to do it (the question not the conversion) cuz I cant figure it out?

hello, i'm still not understanding this question, i tried it my way then modifying according to what was posted..

p= h/ (2 pi * m)

then square this and divide by (1.6x1-&-19) instead of by (2 * 9.1x10^-31)

that is what i tried to no avail

can someone spot what i am doing something wrong here?

soo...


KE = ((h^2)*(n^2))/(8*m*L^2)



m = mass given in problem
h = 6.6E-34
n = quantum number
L = Given Width

The number you get will be in Joules, remember to convert to MeV.


Best of Luck.

I don't think you need to square your original number.

heheh thanks, you're right!

i've tried everything and i still keep getting number 1 and 4 wrong.

What is the m in number 2?

After looking at this for a good 10 minutes I realized what these people are trying to say:

1: (h/2*pi*m) m is the number they give you, the dimension (in my post m = dimension)
((ans)^2)/(2*9.1E-31*1.6E-19) = final ans (negative)

2: same thing but divide ans^2 by 1.6E-19 instead (this didn't work, still working on a solution)

3: 2*L (given) / E-9 = ans (neg)

4: KE = ((h^2)*(n^2))/(8*m*L^2) = ans / 1.6E-13 = ans in Mev (positive)

m = mass given in problem
h = 6.6E-34
n = quantum number
L = Given Width

these are all just other people's explanations organized more clearly, if someone could post a CLEAR description of #2 please do so

Can someone please help with number 2 this is the only one I cant figure out and I have been working on this since yesterday. PLEASE HELP?????

first: h/(2*pi*the #given)=ans
then: ans/1.6E-19=final answer (neg)