Maple TA 26-1 Quiz
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Hint on this section of Hw
You MUST go past the sheets that is stated in the question for 26_1, 2, and 3. Go through all of the lecture sheets.
To get you started on 26_1 #1
Delta P= h/(2pim) where m is given
plug answer into KE = (P)^2/92*9.1*10^-31 then convert to eV
To get you started on 26_1 #1
Delta P= h/(2pim) where m is given
plug answer into KE = (P)^2/92*9.1*10^-31 then convert to eV
super mo- Guest
question 3 and 4
Does anyone have any idea how to do questions 3 and 4 on this I am really struggling.....please help me????
hwilson- Guest
number 2
You are using the same equation as for number 1, but no need to divide by (2 * 9.1e-31) just divide by 1.6e-19.
phy-six- Guest
question 4
Follow the problem on page 22 of the CD, your final answer will be in eV, just convert to megaeV and you get your final answer. Answer is positive.
phy-six- Guest
question 1 and 4
I have tried everything for number one and four can someone please post a detailed description of how they solved it????????????? pleassseee?
cuteprin- Guest
question 4
please someone kindly help out! I've been stuck on question 4 for a long while! thanks!
Guest123- Guest
Number 4 Hint
For number 4 the numbers you are getting are in J, you'd like them in MeV...the conversion is 1.609E-13J = 1 MeV. Best of luck.
6 more c- Guest
question 4
Can you explain how to do it (the question not the conversion) cuz I cant figure it out?
sck105- Guest
number 2
hello, i'm still not understanding this question, i tried it my way then modifying according to what was posted..
p= h/ (2 pi * m)
then square this and divide by (1.6x1-&-19) instead of by (2 * 9.1x10^-31)
that is what i tried to no avail
can someone spot what i am doing something wrong here?
p= h/ (2 pi * m)
then square this and divide by (1.6x1-&-19) instead of by (2 * 9.1x10^-31)
that is what i tried to no avail
can someone spot what i am doing something wrong here?
:)- Guest
Re: Maple TA 26-1 Quiz
soo...
KE = ((h^2)*(n^2))/(8*m*L^2)
m = mass given in problem
h = 6.6E-34
n = quantum number
L = Given Width
The number you get will be in Joules, remember to convert to MeV.
Best of Luck.
KE = ((h^2)*(n^2))/(8*m*L^2)
m = mass given in problem
h = 6.6E-34
n = quantum number
L = Given Width
The number you get will be in Joules, remember to convert to MeV.
Best of Luck.
6 more c- Guest
Hey
After looking at this for a good 10 minutes I realized what these people are trying to say:
1: (h/2*pi*m) m is the number they give you, the dimension (in my post m = dimension)
((ans)^2)/(2*9.1E-31*1.6E-19) = final ans (negative)
2: same thing but divide ans^2 by 1.6E-19 instead (this didn't work, still working on a solution)
3: 2*L (given) / E-9 = ans (neg)
4: KE = ((h^2)*(n^2))/(8*m*L^2) = ans / 1.6E-13 = ans in Mev (positive)
m = mass given in problem
h = 6.6E-34
n = quantum number
L = Given Width
these are all just other people's explanations organized more clearly, if someone could post a CLEAR description of #2 please do so
1: (h/2*pi*m) m is the number they give you, the dimension (in my post m = dimension)
((ans)^2)/(2*9.1E-31*1.6E-19) = final ans (negative)
2: same thing but divide ans^2 by 1.6E-19 instead (this didn't work, still working on a solution)
3: 2*L (given) / E-9 = ans (neg)
4: KE = ((h^2)*(n^2))/(8*m*L^2) = ans / 1.6E-13 = ans in Mev (positive)
m = mass given in problem
h = 6.6E-34
n = quantum number
L = Given Width
these are all just other people's explanations organized more clearly, if someone could post a CLEAR description of #2 please do so
Leland- Guest
question 2
Can someone please help with number 2 this is the only one I cant figure out and I have been working on this since yesterday. PLEASE HELP?????
sjames- Guest
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